okay i think am right not sure..?

Question

What are the solutions for a2 + 7a + 12 = 0?
A) 3 and 4

B) 3 and -4

C) -3 and -4

D) 4 and -3

okay am thinking B please correct me

Answer 1

a^2 + 7a + 12 = 0

(a + 4)(a + 3) = 0

hence a = -4 or -3

so the answer is C

Answer 2

a^2 + 7a + 12 = 0

(a + 3)(a + 4)

a= -3, a= -4

the answers is C not B

Answer 3

your ans is wr

listen first u should break the eqn into factors
here
a^2+7a+12=0
=>a^2+3a+4a+12=0
=>a(a+3)+4(a+3)=0
=>(a+3)(a+4)=0
=>(a+3)=0 or (a+4)=0
=>a=-3 or a=-4 ans

Answer 4

In multiple choice questions involving quadratics you can often find the solution by examining the quadratic.

ax^2 + bx + c = 0

Sum of roots = -b/a
Product of roots = c/a


In this case:
Sum of roots = -7/1 = -7
Product of roots = 12

3+4 =7 ≠ -7 --- A is not correct
3+(-4) = -1 ≠ -7 --- B is not correct
(-3) + (-4) = -7 --- C might be correct
(-3)*(-4) = 12 --- C is correct

Answer 5

Nom the right answer is C. Just check. You can come to the roots using Bhaskara, but in this case it's easy, all you have to do is find 2 numbers whose sum is -7 and whose product is 12. -3 and -4 are such numbers.

Answer 6

I'll correct you. You should be thinking C

Answer 7

it's C. Try to substitute the values.