If one factor of 12x2 + 18x + 12 = 0 is 6, which is another factor?
A) 2x + 1
B) x + 1
C) Both A and B
D) Neither A nor B
2007-06-01 02:34:23 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
the first thing to do is to FACTORISE the equation/expression.
12x^2 + 18x + 12
= 6(2x^2 + 3x + 2)
(oops, we're stuck!)
from the original equation, 12x^2 +18x+12 , a = 12, b=18, c=12.
b^2 - 4ac = 18^2 - 4(12)(12)
= 324 - 576
= (negative number)
oops, x is not a real number.
therefore, neither 2x + 1 nor x+1 is the factor of the equation.
2007-06-01 02:39:58 · answer #1 · answered by English Learner 2 · 0⤊ 1⤋
If you divide out 6 you get
2x^2+3x+2=0 Which has no real solutions so I pick D
2007-06-01 09:38:51 · answer #2 · answered by nmhawthorne 1 · 0⤊ 0⤋
Well, let's see
6(2x^2 + 3x + 2) = 0
x = (-3 +/- sqrt(9 - 4 * 2 * 2))/(2 * 2)
x = (-3 +/- sqrt(-7))/(4)
Well, that won't have real roots, so the answer is D.
2007-06-01 09:41:57 · answer #3 · answered by TychaBrahe 7 · 0⤊ 0⤋
google it
2007-06-01 09:42:38 · answer #4 · answered by Lexi 2 · 0⤊ 0⤋
D...Neither A or B...I think...
2007-06-01 09:38:32 · answer #5 · answered by Anonymous · 0⤊ 0⤋
d)
2007-06-01 09:42:05 · answer #6 · answered by none 2 · 0⤊ 0⤋