(6x2 + 7x - 3) / (9x2 - 6x + 1)
All the 2's mean squared--> to the power of 2
And the x's DON'T mean multiply
2007-06-01 02:17:01 · 7 answers · asked by Muppet 2 in Science & Mathematics ➔ Mathematics
You have to factorioze each expression, then cancel appropriately.
To factorize the top line, notice that 6 = 3 x 2 and 3 = 3 x 1, which gives some clues. After a while, you find
6x2 + 7x - 3 = (3x-1)(2x+3)
Now you try the bottom line!
2007-06-01 02:27:22 · answer #1 · answered by Always Hopeful 6 · 0⤊ 0⤋
on simplifying 6x2 + 7x - 3 you will get (3x-1)(2x + 3 )
and on simplfting 9x2 - 6x + 1 the asn will be (3x - 1) ^2
so you can cut 3x - 1
the asn will be 2x + 3/3x - 1
2007-06-01 09:29:37 · answer #2 · answered by mustafa k 2 · 0⤊ 0⤋
So to start:
(36+7x-3) (81-6x+1)
combining like terms: 117+x-2
not totally sure but this is the way I was shown
2007-06-01 09:23:07 · answer #3 · answered by kjabri 2 · 0⤊ 0⤋
Well, let's see, can we factor these?
x = (-7 +/- sqrt(49 - 4 * 6 * -3))/(2 * 6)
x = (-7 +/- sqrt(49 +72))/(12)
x = (-7 +/- sqrt(121))/(12)
x = (-7 +/- 11)/12
x = -18/12 or x = 4/12
x = -3/2 or x = 1/3
(3x -1)(2x + 3)
The second one is easier to factor
(3x - 1)(3x - 1)
So rewrite as
((3x -1)(2x + 3))/((3x - 1)(3x - 1))
You can cancel out (3x - 1)/(3x - 1)
(2x + 3) / (3x - 1)
2007-06-01 09:32:27 · answer #4 · answered by TychaBrahe 7 · 1⤊ 0⤋
Factor the top to get: (3x-1)(2x+3)
Factor the bottom to get: (3x-1)(3x-1)
Notice that there is a (3x-1) term on the top and the bottom--cancel 1 from each. Now you should have: (2x+3)/(3x-1).
2007-06-01 09:25:22 · answer #5 · answered by bruinfan 7 · 0⤊ 0⤋
is it (6x^2 +7x - 3) / ( 9x^2 - 6x +1) ?
hmm.. is the answer need to be specified wat is the value of x or in the answer with the x it self??
2007-06-01 09:26:36 · answer #6 · answered by Anonymous · 0⤊ 0⤋
[(3x-1)(2x+3)] / [(3x-1)(3x-1)]
=(2x+3)/(3x-1)
2007-06-01 09:28:18 · answer #7 · answered by iyiogrenci 6 · 0⤊ 0⤋