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No - Every time you toss a coin you have a 50% chance of winning. That imply that you can loose forever and a day if you are the unlucky one.

If there is a proviso put into the equation (eg. At least once in 12 times you will win), the % chance of winning will increase to 100% after 11 losses.

2007-05-31 23:17:36 · answer #1 · answered by Francois J V 2 · 2 0

In 12 tosses there is a 1 in 4096 probability that 12 tails will turn up and a 1 in 4096 probability that 12 heads will turn up. Small but non-zero.

The coin has no memory.

It doesn't know it has just had a run of tails, any more than a roulette wheel knows it has just had a run of black (or red)

It is a common delusion people have that "it really must be a head next time after so many tails in a row". This is getting their own subjectivity as to what they personally would expect to happen to interfere with a random process.

There is no point in trying to argue for whatever outcome would personally please you or compensate for the loss you may have incurred so far.

It is muddled thinking like that which causes people to blow a fortune in casinos at roulette when a run of ten or more of the same colour runs into the House Limit when a gambler just redoubles his stake every time he loses.

The only certainty in the long run at roulette is that the house will win in the long term. Individual gamblers may well ride high for an evening or two, but collectively, the gamblers that form the casino's clientele will be, as a group, worse off, simply because of the zero (and double zero) on the wheel.

The only certainty in coin-tossing is that the larger the number of throws recorded, the nearer to 50% overall heads and 50% overall tails the accumulative totals will be.

But on a short run of say 10, 50 or 100 throws. it is probable (but not certain) that the number of heads and tails will show some rather more marked deviation from 50%-50% than it does in the statistical long run.

2007-06-01 02:17:43 · answer #2 · answered by Anonymous · 1 0

No, there is no certainty in probability. If you toss a coin once, you have a 50/50 chance of heads or tails. The second time you toss you still have a 50/50 chance of heads or tails, and so on. The only issue becomes "what is the chance that the same event will recur repeatedly?" The more times tried, the closer the likelihood gets to zero. However, the odds that you can throw a coin one million times and get heads every time, while slim, is still greater than zero. There is no number of tries that will guarantee a result. In probability, anything is possible, it just tells you what is most likely.

2007-05-31 23:16:48 · answer #3 · answered by Josh 3 · 2 0

No, there is no certainity. The probability of winning or not winning in n trials is given by (p + q)^n where p is the probability of winning and q is the probability of not winning. So the probability of not winning is q^n and will not be zero unless n is infinitely large. Thus there is a small but non-zero probability of not winning even once.

But as the number of trials n increases, the probability of winning atleast once increases. That is (p + q)^n - q^n (sum of all terms in the binomial series which contain at least 1 p (winning)).

2007-05-31 23:17:46 · answer #4 · answered by Swamy 7 · 2 0

Nope, there is never a certainity when tossing a coin. The probability of winning will get larger but will not become definite.

2007-05-31 23:13:55 · answer #5 · answered by Anonymous · 3 0

No. The whole premise of probability is that every toss of a coin has the same probability. 50-50

2007-05-31 23:14:16 · answer #6 · answered by jsardi56 7 · 3 0

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2016-12-18 10:36:48 · answer #7 · answered by Anonymous · 0 0

there is no certainty that is why you have to compute for the probability

2007-05-31 23:18:17 · answer #8 · answered by Don V 2 · 3 0

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2007-05-31 23:11:36 · answer #9 · answered by Washington 3 · 2 0

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