In short, what they're asking you to do is to isolate x.
2x + 6y - xy - 6 = 0
2x + 6y - xy = 6
2x - xy = 6 - 6y
x(2 - y) = 6 - 6y
x = (6 - 6y)/(2 - y)
2007-05-31 20:22:58
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answer #1
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answered by Akilesh - Internet Undertaker 7
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2x + 6y – xy – 6 = 0
2x – xy + 6 y – 6 = 0
x ( 2 – y ) + 6( y – 1 ) = 0
x ( 2 – y ) – 6( – y + 1 ) = 0
x ( 2 – y ) = 6( – y + 1 )
x = 6( – y + 1 ) / ( 2 – y )
x = 6( 1 – y ) / ( 2 – y )
2007-06-04 19:58:50
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answer #2
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answered by Pranil 7
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This Site Might Help You.
RE:
Express x in terms of y when 2x+6y-xy-6=0?
2015-08-18 21:41:03
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answer #3
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answered by Berton 1
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2x + 6y - xy - 6 = 0
2x + 6y - xy = 6
2x -xy = 6 + 6y
x (2 - y) = 6 + 6y
x = (6 + 6y) / (2 - y)
explaination : anything you shift from left to right or vice versa will be the opposite
2007-05-31 20:30:53
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answer #4
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answered by ad3l3n3 2
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2x + 6y - xy - 6 = 0
2x - xy = 6 - 6y
x (2 - y) = 6 (1 - y)
x = 6 (1 - y)/(2 - y)
2007-05-31 20:23:26
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answer #5
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answered by Swamy 7
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2x+6y-xy-6=0
Separate x and y terms onto different sides of the equation:
2x-xy=-6y+6
Factorise out so you only have one x (and switch round the other side to make it tidier by not starting with a '-'):
x(2-y)=6-6y
Divide so you only have x on one side:
x=6-6y/2-y
Voila!
2007-05-31 20:22:59
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answer #6
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answered by Anonymous
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2x+6y-xy-6 = 0
2x-xy = 6-6y
x(2-y) = 6(1-y)
x = 6(1-y)/(2-y)
2007-06-01 23:38:31
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answer #7
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answered by billako 6
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2x+6y-xy-6=0
2x-xy = 6-6y
x(2-y) = 6(1-y)
x = 6(1-y)/(2-y)
2007-06-01 00:44:45
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answer #8
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answered by Kemmy 6
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=0
2007-06-04 07:02:28
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answer #9
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answered by Anonymous
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2x+6y-xy-6=0
or 2x-xy+6y-6=0
or x(2-y)=6-6y
or x=(6-6y)/(2-y)
2007-05-31 21:05:55
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answer #10
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answered by Sumita T 3
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