21. If a card is randomly selected from a standard deck of cards, what is the probability that the card is a nine or an ace?
a.1/13
b.2/13
c.3/13
d.4/13
2007-05-31 19:12:14 · 8 answers · asked by danny d 1 in Science & Mathematics ➔ Mathematics
4 nines + 4 aces = 8 cards
8 / 52 = 2 / 13
ans: b
2007-05-31 19:17:51 · answer #1 · answered by Loong 2 · 0⤊ 0⤋
It's just reducing a fraction. Since there are 52 cards in a deck and 4 aces and 4 nines..the fraction of aces and nines to cards in the deck is 8/52
if you divide the top and the bottom by 4 you will get 2/13, which is b.
basically you have a 15.4% chance of drawing a ace or nine (2 divided by 13)
2007-05-31 19:17:52 · answer #2 · answered by alexk 2 · 0⤊ 0⤋
b 2/13 because if there are 52 cards in a deck, then you need a nine or ace thats 8 cards (four from each number) then you put
8 /52 then it will reduce down to 2/13
2007-05-31 19:16:30 · answer #3 · answered by SCHWAA 2 · 0⤊ 0⤋
There are 4 aces and 4 nines
ie 8 cards in total.
P(ace or nine) = 8 / 52 = 2 / 13
ANSWER b)
2007-05-31 20:28:13 · answer #4 · answered by Como 7 · 0⤊ 0⤋
2/13
2007-05-31 20:31:37 · answer #5 · answered by sam 3 · 0⤊ 0⤋
8/52 = 2/13
2007-05-31 19:14:58 · answer #6 · answered by leikevy 5 · 1⤊ 0⤋
b
2007-05-31 19:20:10 · answer #7 · answered by perkijer 3 · 0⤊ 0⤋
b.
2007-05-31 19:22:03 · answer #8 · answered by Anonymous · 0⤊ 0⤋