Explain to me how to solve x^2+2x=120, please!!?

Answer 1

HEHEH.... me and you have the same name! Pleasure meeting you.... what are the chances of THAT happening?!?! =)

x^2 + 2x = 120

add "-120" to both sides .... like this...

(x^2 + 2x) - 120 = 120 -120

x^2 + 2x - 120 = 0 (Knowing FOIL method... you need two numbers that when multiplied will equal -120.... and also add up to +2..... the two numbers are +12 and -10.... because (+12)(-10) = -120 and +12-10 = +2

(x+12)(x-10) = 0

x +12 = 0.... x = -12 is one root
x - 10 = 0.... x = 10 is the 2nd root

Answer 2

the equation is
x^2 +2x=120
take the 120 to l.h.s
the equation becomes
x^2 +2x-120=0
this is quadritic equation
split the middle term now
x^2+12x-10x-120=0
now the first two terms take x common
x(x+12)-10x-120=0
now in the second two terms take 10 common
x(x+12)-10(x+12)
the final factors of the equation are
(x-10)(x+12)
so the value of x=
10,-12ans.

Answer 3

Its an unsightly selection in case you only attempt to ingredient so the quadratic formulation is best extra artwork yet a extra effective looking answer yet first upload 2 to the two factors to set the equation equivalent to 0 the quadratic formulation is (-b±?b^2-4ac)/2a ax^2+bx+c the place as a consequence a=a million b=5 c=2 plug interior the numbers and resolve. (-5±?5^2-4(a million)(2))/2(a million) (-5±?25-8)/2 (-5±?17)/2 you are able to resolve extra besides the shown fact that that's a strange selection so which you would be able to easily leave is as is. i'm hoping this enables

Answer 4

x^2 +2x-120=0 find factors for 120 that will give you +2x

factors of 120 are 1,2,3,4,5,6,10,12,20,24,30,40,60,120

(x+12)(x-10)=0
x=-12 or 10

Answer 5

x^2 +2x-120=0
or x^2+12x-10x-120=0
or x(x+12)-10(x+12)=0
or (x-10)(x+12)=0

or x=10 or x=-12

Answer 6

I might be suffering from sleep deprivation, but does X=10?
10^2=100. 2x10=20. 100+20=120.
120=120.

Answer 7

bring 120 to the other side of the equation. you'll get to:
x^2+2x-120=0.

Then use the general formula to solve quadratics (ax+bx+c=0):
One root is: -b+sqrt(b^2-4ac)
----------------------
2a

One root is: -b-sqrt(b^2-4ac)
----------------------
2a

in your case a=1, b=2 and c=-10; solve using the given formulas

Answer 8

u may do this by usin the 1st answer or by usin quadratic equation method.quadratic equation is slightly difficult 4 starters but it'll give the exact values 4 x.i hope u know that method.

Answer 9

I'm almost positive you need to factor. x^2 = (x+1)(x+1)
Hope that helps!!