L1 with equation x – 7y = 35
L2 with equation 7x + y = 7
2007-05-31 16:47:50 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Perpendicular.
Change them into slope-intercept form:
x - 7y = 35
7y = x - 35
y = (1/7)x - 5
7x + y = 7
y = -7x + 7
Lines that are perpendicular have slopes that are negative reciprocals of each other. Lines that are parallel have exactly the same slope.
The slopes in this case are 1/7 and -7, which are negative reciprocals, so the lines are perpendicular.
2007-05-31 16:52:13 · answer #1 · answered by McFate 7 · 1⤊ 1⤋
L1 with equation x – 7y = 35 subtract x from each side
-7y=-x+35 divide both sides by -7
y=x/7-5
m1=1/7
L2 with equation 7x + y = 7 subtract 7x from each side
y=-7x+7
m2=-7
since -7=-(1/(1/7)) the lines are perpindicular
2007-05-31 23:54:06 · answer #2 · answered by yupchagee 7 · 1⤊ 0⤋
L1: y=1/7x-5
L2: y=-7x+7
The coefficients of x in L1 and L2 are 1/7 and -7 respectively. The coefficient of x in the equations are the gradients of the lines.
As the the coefficients/gradients are negative reciprocals, they are perpendicular.
2007-06-01 00:59:06 · answer #3 · answered by Matthew T 2 · 0⤊ 0⤋
Wow, I've been out of school for a week and I forgot how to do that! lol. I think you'll need some grid paper, if I'm thinking the right thing. Is it rise over run? With something about the x axis or something? Oh, I can't remember! Agh! Sorry
2007-05-31 23:54:28 · answer #4 · answered by Stephanie R 4 · 0⤊ 2⤋
no, they are not parallel because their gradients are not the same but they are perpendicular because their gradients are reciporacls.
2007-06-01 00:00:14 · answer #5 · answered by Oby O 2 · 0⤊ 0⤋