Lazlo prepared a 400.0mL solution of nitric acid (a strong acid) with 3.00 moles of acid. What it eh pH and the pOH of this solution?
2007-05-31 16:47:41 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
C=n/V
C = 3.00*0.4 = 7.5 M
Then use
pH = −log (H+) --as its a strong acid it is 7.5
-log(7.5) = - 0.875
This is a very strong acid.
pOH = 14 - pH
=14.9
2007-05-31 17:05:24 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Watch out for Lazlo. With that type of solution, he can be a real terror. Find the molar conc of the solution (3 moles/0.4 L) = 7.5 Molar. While a pH can be computed, it doesn/t have any significance because you really have a nitric acid solution of water than a water solution of nitric acid.
2007-05-31 16:52:44 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋
400.0 mL solution contains 3 mole acid and nitric acid is a strong acid, so the molarity of the solution is that:
C = 3.00*1000/400 = 7.5 M
Because the concentration of this solution is larger than one, so we can not use pH scale for this solution.
2007-05-31 16:55:29 · answer #3 · answered by ThanhSon D 1 · 0⤊ 0⤋