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it is having to do with logs but how do you find out an exponent when they give you what its equal to for example 3^x=225 it has to be to the nearest tenth. how do you do this please help test tomorrow...:(

2007-05-31 16:06:03 · 5 answers · asked by ugly truth 3 in Science & Mathematics Mathematics

5 answers

easisets method is using log

log225 to base 3 =x

that is
log225
---------- = x (both log225 and log 3 to the base ten)
log3

use log book and find values of both
then divide to get answer.

2007-05-31 16:12:28 · answer #1 · answered by Anonymous · 0 0

Yes, it is having to do with logs. Just select a convenient base and take logs of both sides. For example, with base 10, x log 3 = log 225 and
x = log 225/log 3. The tables or calculators give much more accurate results than nearest tenth.

2007-05-31 23:13:57 · answer #2 · answered by cattbarf 7 · 0 0

this is log base 3 of 225 = x using the change of base formula you can change it to log225/log3 = x and can plug it into a calculator

2007-05-31 23:14:47 · answer #3 · answered by frozenlint 2 · 0 0

whenever u r given an eq like a^y=b where y is the unknown,take log on both sides with base as a.

then u get
y=log b (with base as a)

2007-05-31 23:14:36 · answer #4 · answered by Anonymous · 0 0

4.92994704

2007-05-31 23:17:22 · answer #5 · answered by SagarSaroj 2 · 0 0

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