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solve by completing the square

0.3x+0.1x=0.2

2007-05-31 15:15:34 · 5 answers · asked by :) 5 in Science & Mathematics Mathematics

5 answers

Since we're supposed to be completing a square, I assume the first term is supposed to be 0.3x^2.

In any case, I'd start by multiplying both sides of the equation by 10, to get rid of the annoying decimals:
3x^2 + x = 2
Then divide everything by 3, to give the x^2 term a coefficient of 1:
x^2 + (1/3)*x = (2/3)

Now let's look at completing squares. When you FOIL out (x+a)^2, you get x^2 + 2ax + a^2.
You're trying to find a value of "a" such that 2ax = (1/3)x
2a = (1/3)
a = (1/6)
... so your squared term is (x + (1/6))^2.

When you FOIL out (x + (1/6))^2, you get:
x^2 + (1/3)*x + (1/36)
How do you deal with the (1/36)? Just add a +(1/36) to both sides of your equation:
x^2 + (1/3)*x + (1/36) = (2/3) + (1/36)
Then substitute in the squared term on the left side:
(x + (1/6))^2 = (2/3) + (1/36)
Get a common denominator on the right side, and add:
(x + (1/6))^2 = (24/36) + (1/36)
(x + (1/6))^2 = (25/36)
Then take square roots of both sides:
x + (1/6) = (5/6) or -(5/6)
Subtract (1/6) from both sides, to get:
x = (4/6) or -(6/6)
x = (2/3) or -1

The two possible answers are x=(2/3) and x=-1.

Hope that helps!

2007-05-31 15:28:17 · answer #1 · answered by Bramblyspam 7 · 1 0

x=.5

2007-05-31 15:26:30 · answer #2 · answered by jangojeff1 1 · 0 0

the respond may well be 14. Its somewhat elementary...with the provides of the 1x0...its a risk to get at a loss for words..it happens..=D a million+a million+a million+a million+a million+a million+a million+a million+a million+a million-a million+a million+a million+a million+a million+a million+1x0= 14 it might desire to be extra handy if u rearrange the entire factor 1x0+a million-a million+a million+a million+a million+a million+a million+a million+a million+a million+a million+a million+a million+a million+a million... the 1x0=0 a million-a million=0 and all you gt to do now could be upload something. which totals as much as fourteen yet whilst the question grew to become into as follows: (a million+a million+a million+a million+a million+a million+a million+a million+a million+a million-a million+a million+a million+a million+a million+a million+a million)x0 the respond may well be 0 the nice and cozy button is that if there's a bracket, you may could clean up the bracket first then something of the question. and because there isnt a bracket in this question than you are able to clean up merely with the help of prevalent addition. eg. 2+(2x3)=2+6=8 (2+2)x3=4x3=12

2016-12-30 11:13:28 · answer #3 · answered by Anonymous · 0 0

Multipy by 10 it will look easier after that.

2007-05-31 15:19:15 · answer #4 · answered by cicero 2 · 0 0

0.3x + 0.1X = 0.2
0.4x = 0.2
x = 0.2/0.4
x = 0.5(ANS)

2007-05-31 21:39:34 · answer #5 · answered by zaheen797 3 · 0 0

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