A one liter flask contains a gas that exherts a pressuree of .470 atm. Another flask contains a gas that has a pressure of .205 atm in a volume of one liter. If both gases are combined into a new flask with a volume of one liter, what is the new pressure?
2007-05-31 13:35:11 · 2 answers · asked by 1234567890 5 in Science & Mathematics ➔ Chemistry
.675 atm.
2007-06-01 05:52:48 · answer #1 · answered by ag_iitkgp 7 · 0⤊ 0⤋
to clean up for the style of moles of each gasoline you will derive the equation... n= RT/PV R is a relentless for all proper gases and has the fee of .0821 for this reason to locate n (the style of moles of each gasoline you will plug the given values into the equation and get some thing that regarded like this: n=(.0821*303.2K)/(2.2atm*1L) considering the fact that each and all of the gases you're describing has an identical values for all of our variables interior the equation, (R=.0821, T=303.2K, P=2.2atm, V=1L), each and all of the n values would be an identical... meaning the respond is E! wish that clears issues up a sprint...
2016-11-03 06:20:04 · answer #2 · answered by hanrahan 4 · 0⤊ 0⤋