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If true please explain, if false please give a counterexample.

(a+b)^2 = a^2+b^2


If false also explain

2007-05-31 13:04:52 · 10 answers · asked by brunette12x 1 in Science & Mathematics Mathematics

10 answers

False, because if a=2 and b=3 then (2+3)^2=5^2=25, which clearly does not equal 2^2+3^2=13.

2007-05-31 13:08:56 · answer #1 · answered by bruinfan 7 · 0 0

False-- (1+2)^2 = 3^2 = 9; 1^2 + 2^2 = 1+4 = 5.

theres no way to explain it beyond giving a counterexample... it just isn't true.

2007-05-31 13:08:26 · answer #2 · answered by emp211 3 · 0 0

Its false. Think of it like this..........

if a = 2 and b =3 then

(2+3)^2 =25
2^2 +3^2 =13

Those are definately not equal and you can use other numbers in place of a and b.

An old teacher I once had said that the sum of the squares was not equal to the square of the sum and that simple rule applies here



CD

2007-05-31 13:18:20 · answer #3 · answered by Celestial Dragon 3 · 0 0

False, foil, a^2 + 2ab + b^2

2007-05-31 13:08:27 · answer #4 · answered by richardwptljc 6 · 0 0

It´s false because when you multiply a binomium, you have to multiply each term of the first one with each one of the second and you get a trinomuim. In Spanish it´s called trinomio cuadrado perfecto (something like perfect square trinomius, I dón´t know it´s name in English.

(a+b)^2= (a+b)(a+b)= (a)(a)+(a)(b)+(a)(b)+(b)(b)
=a^2+2ab+b^2

2007-05-31 13:15:44 · answer #5 · answered by anacnorisis 2 · 0 0

false It is a^2 +2ab+b^2

2007-05-31 13:09:28 · answer #6 · answered by Dave aka Spider Monkey 7 · 0 0

False.
(a+b)*(a+b) = a^2 + 2ab + b^2
a^2 + b^2 = (a-b)^2

2007-05-31 13:12:15 · answer #7 · answered by Doug r 2 · 0 0

This is false:

(a+b)^2 = a^2 + 2ab + b^2 (use FOIL method)

This answer D.N.E. a^2 + b^2

2007-05-31 13:09:40 · answer #8 · answered by Dara D 1 · 0 0

True.
distributive property.
i cant really explain beyond that.

2007-05-31 13:08:41 · answer #9 · answered by Brian M 3 · 0 1

NERDS

2007-05-31 13:17:26 · answer #10 · answered by Anonymous · 0 0

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