An object with an initial speed of 5 m/s moves under constant acceleration. Five seconds later its velocity is 10m/s. how far did it travel during this time?
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(Using equation v = (Vo + Vf) / 2 )
2007-05-31 13:03:31 · 3 answers · asked by Tech19 3 in Science & Mathematics ➔ Physics
Average speed is half way between 5 and 10 , or 7.5m/s.
distance = 7.5 x 5 = 37.5 meters.
2007-05-31 13:18:23 · answer #1 · answered by jsardi56 7 · 0⤊ 0⤋
negleting air resistance, the parachutist could be accelerating at a persevering with value. the value of acceleration is Earth's gravitational rigidity (you are able to look that up). time = velocity / acceleration distance = (very final velocity - preliminary velocity)/2 * time
2016-11-24 20:07:24 · answer #2 · answered by Anonymous · 0⤊ 0⤋
These links might help:
http://home.earthlink.net/~dmocarski/chapters/chapter3/ch3page.htm
http://www.chatham.edu/PTI/Math_Connection/Coates_01.htm
2007-05-31 13:17:47 · answer #3 · answered by HappyStarz 5 · 0⤊ 0⤋