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2007-05-31 10:42:23 · answer #1 · answered by Janmik 2 · 0 0

Glad to oblige.

The first is HC*triplebond*C-C(CH2CH2CH3)-
CH2-C*triplebond*C-CH3

The second is a hexagon of carbon atoms with either a circle drawn in the center to denote decentralized bonds, or altewrnating - and = bonds. Next: At the 12 o'clock position put -CH2CH3; at the 2 o'clock and 7 o'clock positions put two -CH3's; and at the 6 o'clock position put -CH2CH2CH3.

The third is CH3CH2CH=CH2CH2OH.

The first answer is contingent on your meaning 3-propyl-1,5-heptadiyne.

2007-05-31 17:51:51 · answer #2 · answered by steve_geo1 7 · 0 0

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