2,035 grams or 814 grams or 651 grams or 88 grams or 37 grams?

Question

how many grams of carbon dioxide are produced when 18.5 moles of oxygenreact with acetylene?2C2H2+2CH2+5O2 (g) 4CO2+2H20

Answer 1

From the coefficients in the balanced equation, you can see that you'll form 4 moles of CO2 for every 5 moles of oxygen that you use. So, multiply the moles of oxygen by 4/5. Then convert that many moles of CO2 into grams by multiplying that the molar mass of CO2.

Answer 2

In ideal conditions according to the reaction you give:

moles of CO2 = 2* moles of acetylene = 4/5 * moles of oxygen

Molecular mass of O2 = 32
Molecular mass of CO2 = 32+12= 44
moles of CO2 = 4*18.5/5 = 14.8
mass of CO2 = 14.8 mole * 44 g/mole =651.2 g

Check the reaction. Acetylene is C2H2 but in the reaction you show there is also CH2 .... nothing to do there
Hope it helps

Answer 3

18.5molO2 x 4molCO2/5molO2 x 44gCO2/1molCO2 = 651gCO2.

The 18.5mol O2 is given. The next factor comes from the balanced equation. The moles O2 cancel leaving moles CO2. The next factor comes from the molecular weight of CO2. The moles CO2 cancel, leaving grams CO2, which was what was wanted.

Answer 4

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