My work
-2(2x^2 - 5x) = -4x^2 +10x
3x(2x^2 -5x) = 6x^3 - 15x^2
I get stuck about right here..
The answer is -4x^2 +13x Can someone pls help me with understanding the steps in solving this? Thanks.
2007-05-31 09:52:28 · 7 answers · asked by grem 3 in Science & Mathematics ➔ Mathematics
Expand & simplify the expression.
3x - 2(2x^2 - 5x)
First: eliminate parenthesis - use the Distribution Method.
3x - 2(2x^2) - 2(- 5x)
3x - 4x^2 - (-10x)
3x - 4x^2 + 10x
Sec: combine "like" terms.
- 4x^2 + 10x + 3x
- 4x^2 + 13x
2007-05-31 10:04:58 · answer #1 · answered by ♪♥Annie♥♪ 6 · 1⤊ 0⤋
You don't need to do anything to the first part of the equation (as there is no bracket by it) which means it is still 3x. The other half of the equation needs the work at this point( as there is a bracket to multiply out). What you need to do is multiply -2 by 2x^2 - 5x so you get -4x^2 + 10 x.
If you then write out the whole equation you get:
3x + (-4x^2 + 10x) then take out the brackets and neaten up you get:
-4x^2 + 13x
2007-05-31 17:03:59 · answer #2 · answered by books_are_heaven 2 · 1⤊ 0⤋
Your second line is incorrect
should be
3x - 4x^2 + 10x
4x^2 + 13x
2007-05-31 16:58:31 · answer #3 · answered by Joe the Engineer 3 · 1⤊ 0⤋
3x - 4x^2 + 10x (multiply the -2 to everything in parenthesis)
13x - 4x^2
10x + 3x = 13x
Hope that helps.
2007-05-31 16:59:29 · answer #4 · answered by a11city 2 · 1⤊ 1⤋
3x-2(2x^2-5x)
-2(2x^2-5x)= -4x^2+10x
3x-4x^2+10x
-4x^2+13x
2007-05-31 17:00:23 · answer #5 · answered by jd 3 · 1⤊ 0⤋
3x-2(2x^2-5x)
3x-4x^2+10x
-4x^2+13x
2007-05-31 17:25:49 · answer #6 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
3x-2(2x^2-5x)
=3x-4x^2+10x
=-4x^2+13 (ans)
2007-05-31 16:59:25 · answer #7 · answered by Diki 1 · 1⤊ 0⤋