hat is the de Broglie wavelength?

Question

For a neutron (mass = 1.675 × 10-27 kg) moving with a velocity of 5.2 × 103 m/s, what is the de Broglie wavelength?

a.2.1 × 10-6 m
b.1.3 × 1010 m
c.486 m
d.7.6 × 10-11 m
e.4.5 × 10-9 m

Answer 1

lambda=h/momentum

= h / (1.67500 * (10^(-27)) * kg * 5.2 * 103 * (m / s)) = 0.738585043 nanometers

This isn't any of your suggestions, but is closest to d. There is likely a typo somewhere.

Answer 2

de Broglie wavelength is given via lambda = h/p (h = plank's consistent = 6.626 x 10^-34 Js, p = momentum) Or lambda = h/mv (m = mass, v = velocity) = 6.626 x 10^-34/(1150 x 24.6) = 2.342 x 10^-38 m

Answer 3

p = h/lambda

p - momentum
h - plancks constant
lambda - wavelength

p = mv

mv = h/lambda

lambda = h/mv
=(6.63*10^-34)/(1.675*10^-27)(5.2*10^3)
=7.61*10^-11

the answer is d

Answer 4

b.1.3 × 10^10 m