Rationalize the denominator:can anyone show me how to do this in steps please
5 over √[6] + √[5]
2007-05-31 06:02:46 · 4 answers · asked by cardoctor61 2 in Science & Mathematics ➔ Mathematics
5/sqrt(6+sqrt(5)).
5/[sqrt(6+sqrt(5))].[sqrt(6)]-sqrt(5)
5/6-5=5 answer
2007-05-31 06:11:08 · answer #1 · answered by Anonymous · 0⤊ 1⤋
to prepare... square Both sides..
at First.. 5² = 25
Second..
(â[6] + â[5])²
= 6 + 5 + 2â[6]â[5])
= 11 + 2â[30]
= 11 + 2(5.XXX) bacause... â[36] = 6
= 11+ 10.XXX (or 11. XXX)
= 21.XXX (or 22.XXX)
So, 5 over â[6] + â[5]
any more question?
contact me~
2007-05-31 13:21:04 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Remember that (a-b)(a+b) = a^2 - b^2. Like (x + 3)(x - 3) = x^2 - 9.
So multiply top and bottom by sqrt(6) - sqrt(5). Then you get
5(sqrt(6) - sqrt(5))/((sqrt(6) + sqrt(5))(sqrt(6) - sqrt(5))) =
5(sqrt(6) - sqrt(5))/6 - 5 =
5(sqrt(6) - sqrt(5))/1 =
5(sqrt(6) - sqrt(5))
2007-05-31 13:14:34 · answer #3 · answered by TychaBrahe 7 · 0⤊ 0⤋
to rationalize the denominator you add the reciprocal to the denominator and to the numerator.
so your answer would be:
5 â6-5â5 over 1
i think this is right!
2007-05-31 13:08:28 · answer #4 · answered by havasuprincess07 2 · 1⤊ 1⤋