English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

If the energy of 1.00 mole of photons is 441 kJ, what is the wavelength of the light?

a.451 nm
b.680 nm
c.732 nm
d.271 nm
e.891 nm

2007-05-31 05:58:22 · 4 answers · asked by Anonymous in Science & Mathematics Chemistry

4 answers

c

2007-05-31 06:15:28 · answer #1 · answered by Chloe G 1 · 0 0

1 mole of photons will contain 6.023 x 10^23 photons (avogadro number (N))

Net energy is 441 kJ...energy per photon is 441/N (kJ)

By the equation E=h * nu where h is planck's constant (6.626068 × 10^-34 m^2 kg / s)
and nu is frequency which you can get by c = nu * lambda

Calculate energy per photon using 441/N.
Then equate this to h * nu
then, use the last equation to get wavelength

.....
wavelength = h * c * N / (441 x 10^3) = 271.44 nm
So the correct answer is
(d)

2007-05-31 13:18:37 · answer #2 · answered by Ohil 3 · 0 0

441,000 J divided by 6.022 E23 gives energy per photon.

Use E = h (nu) to get the frequency.

Use (lambda) (nu) = c to get the wavelength. use 3.00 E8 meters per second.

Convert answer (in meters) to nm

2007-05-31 13:12:58 · answer #3 · answered by ChemTeam 7 · 0 0

b.680 nm

2007-05-31 13:27:48 · answer #4 · answered by ag_iitkgp 7 · 0 0

fedest.com, questions and answers