2x=y+5; (3,1)
First find the slope of the given line 2x=y+5
y=2x-5 <--- Now in slope intercept form
The slope of above line is 2
So the slope of every line || to this line must also have a slope of 2
So new line is y=2x + b, where b is the y-intercept
Now plug in x = 3 and y =1 from the point (3,1) getting:
1=2(3) +b
so b = 1 - 6 = - 5
So required equation is y = 2x -5.
The other three problems are done exactly the same way.
2007-05-31 05:25:16
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answer #1
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answered by ironduke8159 7
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I guess you are asking for the slope intercept form of the line, given a point through which it passes and a line parallel to it.....
Then this is how you proceed
The general equation for the slope intercept is
y = m*x + c
Where m is the slope and c is the intercept
Parallel lines always have the same slope. So first, simply rearrange the equations that you have to look like the slope intercept form (make sure the co-efficient of y is 1 and x is on the other side of the equation...then co-efficient of x is the slope)
So, in the first case,
2x = y + 5 --> y = 2x - 5---> m=2 (you dont need c from this equation)
Now you know that the equation you want will look something like this
y = 2x + c (where you need to find out what c is, depending on the point through which the line passes)
For this, substitute the point in this equation
(3,1)----> 1 = 2*3 + c---->c = -5------>y = 2x-5 is your equation. It is just co-incidental that the given line is the same as the answer....
Similarly proceed for the rest of the equations. (for the second, take the equation as 3x-y+5 = 0... similarly for the fourth)
For the third, I guess you made a typing mistake coz there are two constants (5 and 4/3...which would usually be combined.... if this is a typing mistake, then there is an x term and you have no problems).... otherwise what you have is something like y=c...
Visualize this line. It is parallel to the X axis. If you have your point as (a,b) then the line you want is just y=b....
Hope you are able to solve the remaining problems :)
All the best
2007-05-31 12:27:43
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answer #2
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answered by Ohil 3
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Is the 20 you threw in there to lead us to believe that you will take the answers to those questions and go do the rest on your own?
I have a better idea. Why don't you go and read the Already solved examples and have a go at the questions?
If you have a particular concept you do not understand we will be gald to help you.
2007-05-31 12:21:48
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answer #3
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answered by Anonymous
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since the point is on a parallel line then slope is the same for both lines the plug the coordinates in the equation y=mx+b where m is the slope and y is the y coordinate then solve for b
2007-05-31 12:16:56
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answer #4
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answered by xandyone 5
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2x=y+5
put equ in y=mx+b form
y=2x-5
slope=m
m=2
y-intercept when x=0
y=2(0)-5
y=-5
y-intercept=-5
2007-05-31 12:35:37
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answer #5
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answered by R 2
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Your question isn't really clear. Could you give the original context? Then I could have a go at it.
2007-05-31 12:14:46
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answer #6
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answered by Mock Turtle 6
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