What is the formula to find the area of a sector, when the length of the 2 sides and as well as the length of the curve is given?
2007-05-31 04:56:38 · 6 answers · asked by royal l 1 in Science & Mathematics ➔ Mathematics
The length of the circle arc (l) is rx where r is the radius of the circle and x is the central angle in radians) that subtends the arc.
The area of the whole circle is pi*r^2
The area of the sector = x/(2pi)*pir^2 = xr^2/2.
But x = l/r so Area = lr/2
2007-05-31 05:13:16 · answer #1 · answered by ironduke8159 7 · 0⤊ 0⤋
You can't do this for a curve. Maybe for a triangle or if the equation of the curve is given then you'll be able to do it
2007-05-31 04:59:55 · answer #2 · answered by Mock Turtle 6 · 0⤊ 0⤋
θ₁ = (arc length)/radius = 105/73.4 ≅ 1.43 radians θ₂ = = 2π - θ₁ ≅ 4.85 radians θ₁ < θ₂, so θ₁ is the angle of the minor sector, and θ₂ is the angle of the major sector. area of circle = 2·73.4π ≅ 16925.5 units² area of minor sector = 16925.5×θ₁/(2π) ≅ 3853.5 units² area of major sector = 16925.5 - area of minor sector ≅ 13072.1 units²
2016-05-17 21:14:48 · answer #3 · answered by ? 3 · 0⤊ 0⤋
Area=(m/360)*Pi*r^2
m= measurement of central angle (in degrees)
r= radius
2007-05-31 04:59:29 · answer #4 · answered by C-Wryte 3 · 0⤊ 0⤋
Reffer cbse class 8,9 maths book u will get good aanswer.
2007-05-31 05:00:56 · answer #5 · answered by Anonymous · 0⤊ 0⤋
piR^2 (2piR/leanght of curve)
(r is side of sector)
2007-05-31 05:03:03 · answer #6 · answered by zspace101 5 · 0⤊ 0⤋