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75 people increase to 2 million in 430 years

2007-05-31 04:04:20 · 2 answers · asked by Don Verto 7 in Science & Mathematics Mathematics

2 answers

If people increase in geometric progression with a common ratio of r per year, startinmg with a people, the number of people after n years is ar^(n–1) (standard formula for a geometric progression).

In your problem the only thing that changes is the number of people you start with, a. Since r and n are unchanged, you can just scale up the result.

If 75 people grow to 2,000,000 people in 340 years, then at the same rate of growth 2,000,000 people will grow to 2,000,000 x 2,000,000 / 75 = 53 billion approx.

Quite a lot.

2007-05-31 04:35:36 · answer #1 · answered by rrabbit 4 · 0 0

No. - Starting Population.
N - Population.
R - Number factor.
t - time factor.
N = No.e^RT

First calculate the R value.
N = No.e^RT
N/No. = e^RT (take logs).
Ln (N /No.) = RT
R = Ln (N /No.) / T
R = Ln (2*10^6 /75) / 340
R = 10∙191 169 62 / 340
R = 0∙029 974 028

Now calculate the new population.
N = No.e^RT
N = (2*10^6)e^(0∙029 974 028)(340)
N = (2*10^6)e^10∙191....
N = (2*10^6)(26,666∙66...)
N = 5∙33...*10^10
N = 53,333∙33... Million People.

2007-05-31 11:50:13 · answer #2 · answered by Sparks 6 · 0 0

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