Another chemistry question?

0 ⤊

Another chemistry question?

How many moles of argon are there in 20.0L, at 25oC and 96.8 kPa?

2007-05-31 03:22:22 · 2 answers · asked by <3 1 in Science & Mathematics ➔ Chemistry

2 answers

R = 8.314 L • kPa / K• mole
T = 25ºC + 273 = 298 K
P = 96.8 kPa
V = 20L

PV = nRT

n = PV/RT = (96.8kPa*20L)/(8.314 L • kPa / K• mole)*(298K)

= 0.78 moles

2007-05-31 03:57:38 · answer #1 · answered by Dr Dave P 7 · 0⤊ 0⤋

Again, use the ideal gas law, PV=nRT and solve for n. You will need to convert your temperature to Kelvin, and depending on the value of R that you use, you may have to convert the pressure to atmospheres, or use R with units of LkPa/mol K.

2007-05-31 10:28:31 · answer #2 · answered by hcbiochem 7 · 0⤊ 0⤋