Amal reversed the digits in amount of a check of an underpaid customer by 36$. the sum of the digits in the two-digit amount was 8. Find the amount of the check
2007-05-31 02:37:22 · 4 answers · asked by Riley 1 in Science & Mathematics ➔ Mathematics
Let the amount of the cheque be 10x+y
Digits are x and y
If you reverse the digits, the number becomes 10y+x
10x+y-(10y+x)=36
9x-9y=36
x-y=4
x+y=8
2 equations. Solve for x and y
Add the equations
2x=12
x=6
6+y=8
y=2
The amount of the cheque was 10*6 + 2 = $62
Reverse the digits -- $26
62-26 = 36
2007-05-31 02:46:24 · answer #1 · answered by gudspeling 7 · 0⤊ 0⤋
Let the first digit in the amout be a.
Then the second was 8 - a .............(1)
(10a + 8 - a) - (10(8 - a) + a) = 36
Expand the brackets:
9a + 8 - 80 + 10a - a = 36
Add the terms in a and the absolute terms:
18a - 72 = 36
Divide by 18:
a - 4 = 2
Add 4
a = 6
From (1), the second digit was 8 - 6 = 2.
The check was for 10a + 2 = 10*6 + 2 = $62.
2007-05-31 09:50:29 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Digits are 6 and 2.
62 - 26 = 36
2007-05-31 09:42:34 · answer #3 · answered by Doctor Q 6 · 0⤊ 0⤋
62 and 26
2007-05-31 09:46:51 · answer #4 · answered by gebobs 6 · 0⤊ 0⤋