f(x)=g(x).(x-1)(x-2)(x-3). If f(x) is divided by (x-1),(x-2) and (x-3), the remainders are 4,-1 and 2 respectively. Using partial fractions or otherwise, find an expression for f(x).
2007-05-31 00:00:25 · 3 answers · asked by Stormy Knight 1 in Science & Mathematics ➔ Mathematics
I think question is wrong
because (x-1) (x-2) and(x-3) devide f(x) without remainder
f(x)/(x-1) = g(x)(x-2)(x-3)
2007-05-31 02:35:46 · answer #1 · answered by Mein Hoon Na 7 · 0⤊ 0⤋
resolve for z first: z=(x^2 + y^2)/(x+y) now take your 2 partial derivatives: dz/dx = (x^2 + 2 x y - y^2)/(x + y)^2 dz/dy= (-x^2 + 2 x y + y^2)/(x + y)^2 now, if the equation above is to be satisfied, then the version must be 0. or: (?z/?x - ?z/?y)^2 - 4(a million - ?z/?x - ?z/?y) = 0 i'm going to provide help to do the artwork, whether it does upload as much as 0
2016-10-30 07:53:30 · answer #2 · answered by ? 4 · 0⤊ 0⤋
YA I ALSO THINK SO... f(x) is clearly divisible by (x-1), (x-2),(x-3).............plz check the qst...
2007-05-31 20:24:09 · answer #3 · answered by nupur 2 · 0⤊ 0⤋