How do you calculate the molarity of an aqueous NaOH solution?

Question

if 30.10 mL of .500 M H2SO4 is required to reach the end point when titrated against 10.00mL of the NaOH solution?
The balanced chemical equation for this neutralization is-

H2SO4 + 2 NaOH ---> Na2SO4 + 2 H2O

Thank you for your help.

Answer 1

the mole of H2SO4 = 15.05mmoles
thus the mole of NaOH should be 30.10 mmoles

the molarity of NaOH = 30.10 : 10
= 3.01 M

Answer 2

I find the best way to deal with titrations is to use normality
and then you can use the formula: N1 * V1 = N2 * V2.

First convert molarity to normality :

Normality = Molarity * n

where n = number of H+ (for acids) or OH- (for bases)
that take part in the reaction.

For H2SO4, n = 2 and for NaOH, n = 1

So, normality of H2SO4 = 0.500 *2 = 1.000 N

Now, N1 * V1 = N2 * V2 becomes :

1.000 * 30.10 = N2 * 10.00

Therefore, N2 = 1.000 * 30.10 / 10.00 = 3.01 N

The normality of NaOH is thus 3.01 N.

Now convert this back to molarity using the equation.

Molarity = Normality / n (where n = 1 for NaOH)

Therefore, molarity of NaOH = 3.01 / 1 = 3.01 M

EDIT:
Just wanted to clear up a possible misunderstanding of the
word "normality". I'm pretty sure it refers to the number of
reactive ions in a single molecule only, and does not take
into account the total number of molecules that take part in a
reaction. So the "2" in 2NaOH of the equation is irrelevant.
Thought I'd add that because I've stated that for NaOH, n = 1,
and it does seem confusing that 2NaOH's are reacting, but
I think that's the way it is, although I'm willing to be
admonished if I've erred.

Answer 3

I believe the formula is Molarity = -log(pH) You would have to do it on a calculator. However, because the molarity is an integer, the Molarity should be 1x10^(-13) (one times ten to the negative thirteen)

Answer 4

number of moles H2SO4= molarity(mol/dm3) X vol (dm3)
so: number of moles= 15.05

no of moles NaOH = 15.05 X 2 = 30.1

MOLARITY OF NaOH= 30.1/0.01
answer: 3010M

im not quite sure about the calculation, but the formulas are definitely accurate

Answer 5

30.1/1000 x 0.5 x 2 x 1000/10