is it possible to integrate 2x * sqrt (3x) ?
if so, can you possibly show your calculations or something and not from a calculator
2007-05-30 19:29:26 · 4 answers · asked by Jack Bauer 3 in Science & Mathematics ➔ Mathematics
2x * sqrt(3) * x^1/2
= 2*sqrt(3) * x^3/2
Integrating, we get
2*sqrt(3) * 2/5 * x^5/2 + C
= 4 * sqrt(3) / 5 * x^5/2 + C
2007-05-30 19:34:19 · answer #1 · answered by Dr D 7 · 1⤊ 0⤋
â«2xâ3x dx
=2â3 â«x^(3/2) dx
=2â3*(2x^(5/2))/5+C
the key to this integral is simplifying the integrand before taking the antiderivative
2007-05-31 02:37:10 · answer #2 · answered by blackknightu1 1 · 0⤊ 0⤋
yes, 2x*sqrt(3x) = 2sqrt(3)x^3/2 so the integral is
2*sqrt(3)*(2/5)*x^5/2
(4/5)*sqrt(3)*x^5/2
2007-05-31 02:35:30 · answer #3 · answered by cp_exit_105 4 · 0⤊ 0⤋
I = â« 2x.â(3x).dx
I = â« 2.â3.x^(3/2).dx
I = 2.â3.x^(5/2) /(5/2) + C
I = (4.â3/5).x^(5/2) + C
2007-05-31 02:36:20 · answer #4 · answered by Como 7 · 1⤊ 0⤋