how many moles of hydrochloric acid are present in reaction?

Question

a 0.500L solution of 700M hydrochloric acid is used to netralized a 250.0g sample of calcium hydroxyde. calcium chloride , a chemical that is used to control highway dust, strengthen concrete mixes and add flavor to foods, is produced by the reaction.

Answer 1

As the HCl available in the market contains maximum of 11 M concentration,hence in your question concentration of HCl can not be more than 11M, hence it should be 7.00 M .

The reaction taking place here is ;

Ca(OH)2 +2HCl ------> CaCl2 +2H2O;

It indicates that 2 moles of HCl react with one mole of calcium hydroxide. Calcium chloride available is 250 g, which is equivalent to 250/74 M =3.38M;
So, the moles of HCl consumed will be =2*3.38 =6.76 M
Remaining HCl moles =7.00-6.76 =0.24 M
Therefore,answer =0.24M HCl

Answer 2

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Answer 3

The reaction is

2HCl + Ca(OH)2 ---> CaCl2 + 2H2O

The moles of HCl is 0.5*700 = 350. One mole of Ca(OH)2 will neutralize 2 moles of HCl. The molecular mass of Ca(OH)2 is 74, so 250g represent 250/74 = 3.38 moles. This will neutralize 2*3.38 = 6.76 moles of HCl. You started with 350, so you have 343.24 moles of HCl left.

(Note: you wrote 700M, but I think you mean 70.0 M of HCl. In this case the remaining HCl will be 35 - 7.76 = 28.24 moles; if you meant 7.00, then no HCl remains. 1L of pure HCl contains 40.6 moles, so the theoretical max concentration of HCl is 40.6M.)

Answer 4

i'm undecided what you're asking.. the type of type of moles of calcium hydroxide is.. mass / Mw(Ca hydroxide) 250/seventy 4 = 3.38M what's with each and all the tips relating to the acid? 2HCl + Ca(OH)2 -> CaCl2 + 2H2O