2007-05-30 18:01:46 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
so what are you trying to get to and are ther any ( ). because from what i can tell there are many different ways to read this problem.
4b+5d-c all over a
4b +((5d-c) /a)
4b+5d-(c/a)
2007-05-30 18:09:54 · answer #1 · answered by why_oh_why_me2001 1 · 0⤊ 0⤋
To add or subtract fractions, everything needs to have the same denominator, so we'll multiply 4b and 5d by (a/a) which is legal because (a/a) = 1.
4b+5d-c/a
(a/a)*4b + (a/a)*5d-c/a
4ab/a + 5ad/a - c/a
Now we can group terms.
(4ab + 5ad - c) / a
2007-05-31 01:10:52 · answer #2 · answered by sft2hrdtco 4 · 0⤊ 0⤋
It may be that you mean:-
(4b + 5d - c) / a
Everything on top line has to be divided by a:-
4b/a + 5d/a - c/a
Hope this helps.
2007-05-31 02:16:43 · answer #3 · answered by Como 7 · 0⤊ 0⤋
so what's the question? yes that's addition with fraction.
2007-05-31 01:06:44 · answer #4 · answered by i a 4 · 0⤊ 0⤋