Physics Problem ...................... Help me out ............?

Question

A spring is fixed at the bottom end of an incline of inclination 37(degree). A small block mass 2 kg starts slipping down the incline from a point 4.8 m away from the spring. The block compresses the spring by 20 cm, stops momentarily and then rebounds through a distance of 1 m up the incline. Find :-

a) the friction co-efficient between the plane of the incline and the block
b) the spring constant of the spring. Take g=10 m/(s^2)


diagram is available in HC Verma (vol^m 1) , page 135 , problem no. 43 , fig- 8-E7

The original answer is ....
a)0.5 b)1000 N/m

Answer 1

I Can't help u.....

Answer 2

4.8mgsin(35°) - 4.8μmgsin(35°) = (1/2)(0.2)^2k + 0.2μmgsin(35°)
(1/2)(0.2)^2k - 0.2μmgsin(35°) = mgsin(35°) + μmgsin(35°)
4.8mgsin(35°) - 5μmgsin(35°) = (1/2)(0.2)^2k
(1/2)(0.2)^2k - 1.2μmgsin(35°) = mgsin(35°)
mgsin(35°)(4.8 - 5μ) = (1/2)(0.2)^2k
(1/2)(0.2)^2k = mgsin(35°)(1 + 1.2μ)
4.8 - 5μ = 1 + 1.2μ
6.2μ = 3.8
μ = 0.6129
k = 976.19 N/m