The area of a trapezoid is given by
A= 1/2h(a+b),
where h is the height of the trapezoid, and a and b are the lengths of the upper and the lower base, respectively.
Solve for a.
2007-05-30 16:53:52 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
1/2 h(a+b)=A
=> h(a+b)=2A [multiplying both sides by2]
=>a+b=2A/h [dividing both sides by h]
=>a=(2A/h)-b[subtracting b from both sides
2007-05-30 16:58:51 · answer #1 · answered by alpha 7 · 0⤊ 0⤋
Start by mutiplying both sides of the equation by 2:
2A = h(a+b)
divide both sides by h:
2A/h = a + b
subtract b from both sides:
2A/h - b = a
2007-05-31 00:02:24 · answer #2 · answered by cryptogramcorner 6 · 0⤊ 0⤋
A= 1/2h(a+b)
2A=h(a+b) both side times 2
2A/h=a+b both side divide by h
(2A/h)-b=a
2007-05-30 23:57:26 · answer #3 · answered by ۞_ʞɾ_ 6 · 0⤊ 0⤋
A= 1/2h(a+b)
A/.5h=a+b divide both sides by .5h
(A/.5h)-b=a subtract b
a= (2A/h)-b make it 2A over h to get rid of teh decimal in teh denominator
2007-05-31 00:00:06 · answer #4 · answered by =) 2 · 0⤊ 0⤋
A = ah/2 + bh/2
ah/2 = A - bh/2
ah = 2(A-bh/2)
ah = 2A - bh
a = 2A/h - b
2007-05-30 23:57:13 · answer #5 · answered by TychaBrahe 7 · 0⤊ 0⤋
A = 0.5 h (a + b)
A = 0.5 h a + 0.5 h b
A - 0.5 h b = 0.5 h a
(A / 0.5 h) - (0.5 h b / 0.5 h) = a
(A / 0.5 h) - b = a
2007-05-31 00:00:45 · answer #6 · answered by skipper 7 · 0⤊ 0⤋