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(z-5)^2 = 6
solve for z
PLEASE :D

2007-05-30 16:48:04 · 3 answers · asked by Hally K 1 in Science & Mathematics Mathematics

3 answers

(z-5)^2 = 6

z -5 = +/- sqrt (6)
z = 5 +/- sqrt(6)

2007-05-30 16:50:53 · answer #1 · answered by michael_scoffield 3 · 0 0

z² - 10z + 25 = 6
z² - 10z + 19 = 0
z = [10 ± √24] / 2
z = [10 ± 2√6 ] / 2
z = 5 ± √6

2007-05-31 02:58:10 · answer #2 · answered by Como 7 · 0 0

(z-5)^2 = 6

z-5 = +/- (sqrt 6)

z = 5 + sqrt 6

.... and z = 5 - sqrt 6

2007-05-30 23:52:00 · answer #3 · answered by blueskies 7 · 0 0

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