I need help with this Algebra question!!!?

Question

Okay! Please answer all three of these problems....show me your work! I dont understand this at all! I need your help to explain them! Thank you!!

1. c + 2 / c^2 times 3c/c^2 - 4


2. a^2 - x^2 / a^2 times a / 3x-3a


3. 2x + 2y(over)x^2 / x^2 - y^2(over) 4x

these are fractions!!

Answer 1

1. c + 2 / c^2 times 3c/c^2 - 4
(c+2)/c^2 times 3c/[(c+2)(c-2)]
= 3/[c(c-2)]

2. a^2 - x^2 / a^2 times a / 3x-3a
[(a-x)(a+x)]/a^2 times a/[3(x-a)]
= -(a+x)/(3a)

3. 2x + 2y(over)x^2 / x^2 - y^2(over) 4x
(2(x+y))/x^2 divided by [(x+y)(x-y)]/4x
=(2(x+y))/x^2 times 4x[(x+y)(x-y)]
= 8/[x(x+y)]

Answer 2

it is difficult to under stand what you are asking
when displaying fractions place the top part in parenthesis then place a / then put the bottom in parenthesis
also use a * instead of saying times
example 5 times 2 over 6 times 8 should be
(5*2)/(6*8)
is there are more parts to the equation then just the fraction place the whole thing in parenthesis
example
if you wanted to multiply 5 times 2 over 6 times 8 by 5 you would type
((5*2)/(6*8))*5

Answer 3

1.
(c + 2 / c^2)(3c/(c^2 - 4) =
((c + 2)/c^2)(*3c/(c + 2)(c - 2) =
3/(c - 2)c
2.
(a^2 - x^2)a^2)(a/3x - 3a) =
(a + x)(a - x)a/-3(a - x) =
- (a + x)a/3

3.
((2x + 2y) / x^2) / ((x^2 - y^2) / 4x) =
(2(x + y) / x^2) * (4x / (x + y)(x - y)) =
(2 / x) * (4 / (x - y)) =
8 / (x(x - y))

Answer 4

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