algebra help please?

Question

I need to rationalize the denominator can anyone help and show me how to do it please, 5/√[6] +√[5] , Thanks bunches

Answer 1

multiply top and bottom by √6 - √5, getting

[ 5√6 - 5√5 ] / (6 - 5) = 5√6 - 5√5

Answer 2

Multiply the first by the sqrt(6)/sqrt(6). You should end up with:

(5*sqrt(6))/6, not pretty but the correct form. Multiply the second one by 6/6 and adding them then is:

[5*sqrt(6) + 6*sqrt(5)]/6

This is for the problem (5/sqrt(6)) + sqrt(5). Philo has the right answer if you inadvertantly left out parenteses and both squareroots are in the denominator as a sum. That is, is the problem is 5/[sqrt(6) + sqrt(5)]

Answer 3

it's very simple. just change the sign in the denominator and multiply it in the denominator as well as numerator.here it follows
=5/~6+~5 * ~6-~5/~6-~5
= 5*~6-~5/~6+~5*~6-~5
= 5*~6-~5/~6*~6-~5*~5
= 5*~6-~5/6-5
= 5*~6-~5/1
= 5*~6-~5
assume '~' as a square root

Answer 4

try mathassignment.com