√[64x^10y^2z^46] I need to simpify this can anyone explain how to do this for me I would truely appreciate it.
2007-05-30 16:03:19 · 10 answers · asked by ambi565 2 in Science & Mathematics ➔ Mathematics
ok so you want to simplify
√64x^10y^2z^46
√8*8x*x*x*x*x*x*x*x*x*x*y*y
*z*z*z*z*z....(46 times)
ok so when every you 2 of the same variables or numbers you could bring them out
since you have 2 8's you could bring one out
since you have 2 y's you could bring oune out
since you have 10 x's you could bring 5 out
since you have 46 z's divide by two is 36, so you could bring 36 out.
final answer: 8x^5yz^23
:)
2007-05-30 16:25:42 · answer #1 · answered by ღßutterflyღ 3 · 0⤊ 0⤋
â[64x^10y^2z^46]
â[8^2 x^10 y^2 z^46]
= 8 x^(10/2) y^(2/2) z^(46/2)
= 8 x^5 y z^23
2007-05-30 23:06:30 · answer #2 · answered by michael_scoffield 3 · 0⤊ 0⤋
it's easy, you just have to divide the power by 2 so that the square root sign will be eliminated.
from â[64x^10y^2z^46], you will have 8(x^5)(y)(z^23) or 8x^5yz^23.
2007-05-30 23:31:40 · answer #3 · answered by Lucas Vandross 3 · 0⤊ 0⤋
= â(64.x^(10).y².z^(46)
= 8.x^(5).y.z^(23)
Note (as a check):-
8 x 8 = 64
x^(5) X x^(5) = x^(10)
y X y = y²
z^(23) X z^(23) = z^(46)
2007-05-31 03:30:36 · answer #4 · answered by Como 7 · 0⤊ 0⤋
you simply take out the squares out of the square root symbol
â[64x^10)(y^2)(z^46)]
it should look something like
8â[x^10)(y^2)(z^46)]
then take each power and divide it by 2 and it will be it's root thus:
8*(x^5)*(y)*(z^23)
2007-05-30 23:08:01 · answer #5 · answered by WraitH 3 · 1⤊ 0⤋
sqrt(64x^10 y^2 z^46)
break it down into:
=sqrt(64)sqrt(x^10)sqrt(y^2)sqrt(z^46)
2007-05-30 23:07:50 · answer #6 · answered by Jen 3 · 0⤊ 0⤋
Michael is correct.
2007-05-30 23:25:59 · answer #7 · answered by April 6 · 0⤊ 0⤋
try mathassignment.com
2007-05-30 23:20:52 · answer #8 · answered by flibberpash 2 · 0⤊ 0⤋
it is easy
2007-05-30 23:07:10 · answer #9 · answered by Anonymous · 0⤊ 0⤋
holy crap.
2007-05-30 23:05:45 · answer #10 · answered by Anonymous · 0⤊ 1⤋