A gas at 85°C occupies a volume of 0.67 L. At what Celsius temperature will the volume increase to 1.02 L?

Answer 1

If the pressure remains constant
pV=nRT
p*0.67=nR (85+273)
p*1.02=nRT
1.02/0.67=T/358 so T =545 oK =272 oC

Answer 2

At consistent tension, quantity and Kelvin temperature are without postpone proportional (Charles' regulation). V1/T1 = V2/T2 V1 = preliminary quantity = 0.sixty seven L T1 = unique Kelvin temperature = fifty 9 C + 273 = 332 ok V2 = new quantity = a million.39 L T2 = new Kelvin temperature 0.sixty seven / 332 = a million.39 / T2 (0.sixty seven)(T2) = (332)(a million.39) T2 = (332)(a million.39) / (0.sixty seven) = 689 ok . . . - 273 = 416 C

Answer 3

if you know the coeff. of expansion of the given gas then you can solve this..