2007-05-30 15:20:30 · 6 answers · asked by ash_rash_13 1 in Science & Mathematics ➔ Chemistry
1N * 14g = 14g
3O * 16g = 48g
1 Ag * 107.87g = 107.87g
Total = 169.87g
Use google to perform 2.554 / 169.87
2007-05-30 15:29:49 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Total up the molecular mass of each atom in AgNO3. That means 1 atom of silver, 1 atom of nitrogen and 3 atoms of oxygen
The total is the molecular mass. Divide the 2.554 g by this number and you will have moles
2007-05-30 15:24:06 · answer #2 · answered by reb1240 7 · 0⤊ 0⤋
All you need to do is divide 2.554 g by the molecular weight of AgNO3. That will give you the number of moles of AgNO3
2007-05-30 15:27:48 · answer #3 · answered by Anonymous · 0⤊ 0⤋
I dont have a periodic table in front of me but you just simlpy add up the Silver The Nitogen And the oxagen and then take the 2.554g and divade that by the mass of AgNO3.
2007-05-30 15:25:04 · answer #4 · answered by bruns778 2 · 0⤊ 0⤋
divide 2.554 by the molar mas of AgNO3
2007-05-30 15:49:09 · answer #5 · answered by rainbowchaser92 2 · 0⤊ 0⤋
? moles AgNO3 = (2.554 g * 1 mole AgNO3) / 169.874g
= .0150 mole
169.874 = 107.868(mol.wt. of Ag) + 14.006( mol. wt. of N) + 48.000(mol.wt. of O)
2007-05-30 15:38:06 · answer #6 · answered by Pritpal S 1 · 0⤊ 0⤋