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Benzene's density is 0.88 gm/ml, its heat of vaporization is 20.0 KJoules per mole, its heat of fusion is 10.0 KJoules per mole, its heat capacity is 0.50 KJoules per mole-degree C for liquid benzene, o.25 KJoules per mole-degree C for solid benzene, and 0.125 KJoules per mole-degree C for gaseous benzene. Calculate the following:
A. The energy required to heat 390. grams of benzene from 300 C to 600 C.
B. The energy requred to cool 3.90 micrograms of benzene from 60 C to 20 C.
C. The energy removed to heat 39.0 kilograms of benzene from -100 C to -50 C.
D. The volume occupied by 1 kilomole of liquid benzene at 25 C and the volume occupied by 1 nanomole of benzene as a vapor at STP (assume an ideal gas)

2007-05-30 14:37:10 · 2 answers · asked by Anonymous in Science & Mathematics Chemistry

2 answers

ENERGY = W Cp delta T
where W is weight in moles
Cp is heat capacity in KJoules per mole per deg K
delta T is temperature change.
Parts A,B, and C deal with one-phase benzene so the above relation holds.
Part D. Convert 1 kilomole (that's alot) to grams. You need molecular weight (78) to do this. Then divide by density to get volume. One mole of an ideal gas occupies 22.4 Liters. One namomole is 1/1000000000 of a mole, so the volume is reduced accordingly. You can figure out the volume units you want to use (like cubic mm).

2007-05-30 14:47:17 · answer #1 · answered by cattbarf 7 · 0 0

Boiling point is 100 Celsius or 180 Fahrenheit Freezing or melting is 0 Celsius or 32 Fahrenheit The differences would be 100 and 180 degrees respectively. Variable factors apply that affect these temperatures, such as air pressure and oxygen content, but these are the standards.

2016-05-17 08:53:56 · answer #2 · answered by Anonymous · 0 0

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