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How can graph this without using transformation.
y=2sin(@-45)+2

Thanks

2007-05-30 14:25:09 · 3 answers · asked by dijimon 1 in Science & Mathematics Mathematics

3 answers

I take it "@" is supposed to be an x or theta, and that you're graphing y against this.

Think of what y = sin(x) looks like. The "+2" means weren't starting it up higher at y=2 instead of y=0. The "x-45" means that we're shifting things over by 45 (which I'll assume is in degrees, so that you really want pi/4). So shift the whole thing to the right by pi/4. The "2" in front means the amplitude is 2. So keep the horizontal line of symmetry (y=2) the same and stretch the peaks up by 1 and the valleys down by 1.

2007-05-30 14:33:17 · answer #1 · answered by Anonymous · 0 0

I don't know what transformation you need to apply. Just go back to your definitions. The constant 2 (not to be confused with the coefficient of the sine term) tells you that the sine wave will have an apparent zero value at y=2. The coefficient 2 tells you that the amplitude of the sine wave is 2, so the wave will have a max at y=4 and a minimum at y=0. The (-45) tells you that sine wave is shifted from its usual position on the x-axis to the left. Thus at x=0, the value of sin(@-45) is the same as sin(-45).
Look ma, no transformations.

2007-05-30 14:33:45 · answer #2 · answered by cattbarf 7 · 0 0

evaluate that the Y axis is the commencing element. Cos starts severe, Sin starts at 0. they might look alike, like make an identical shape, yet they don't seem to be an identical. I wish i ought to describe it extra effectual and extra, sry

2016-11-23 19:57:36 · answer #3 · answered by ? 3 · 0 0

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