A sample of argon has a volume of 0.43 mL at 24 degrees C. At what temperature in degrees Celcius will it have

Question

A sample of argon has a volume of 0.43 mL at 24 degrees C. At what temperature in degrees Celcius will it have at a volume of 0.57 mL at constant pressure?

Answer 1

From pV= nRT, we can write V= (nR/p) T. The stuff inside the ( ) is a constant, so V2/V1 = T2/T1. You have V2 (0.57) and V1 (0.43) and T1 (24+273). So solve already!

Answer 2

The ideal gas law says pv=nrt. If p, n, and r are constant, then because p/nr = t/v, t/v is constant, too. T1/V1 = T2/V2. Therefore, T2 = T1*V2/V1.