Two Similar triangles have corresponding sides with lengths 3 and 9. If the area of the first traingle is 12, what is the area of the second triangle?
2007-05-30 14:17:47 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
The ratio of the area of similar triangles is equal to the square of the ratio of the length of the corresponding sides.
Area Second Triangle = 12*(9/3)² = 12*9 = 108
2007-05-30 14:22:33 · answer #1 · answered by Northstar 7 · 1⤊ 0⤋
i could say "particular", the two have a 40 5 degree attitude. For a triangle, all angles ought to upload as much as a hundred and eighty stages. For triangle FSH, attitude F= sixty two, attitude S= 40 5, meaning that attitude H= will equivalent seventy 3. an identical is going for triangle LVQ. in basic terms in this triangle, attitude L= seventy 3. consequently, those triangles have an identical attitude measurements. One may be bigger than the different, however the angles are each and each of an identical. solid success!
2016-11-23 19:56:56 · answer #2 · answered by ? 3 · 0⤊ 0⤋
108. Height of first triangle is 8. corresponding height of second triangle is 24. Hence area is 108
2007-05-30 14:26:40 · answer #3 · answered by kuppai 1 · 1⤊ 0⤋
36. You have to create a proportion. 3/9=x/12
2007-05-30 14:22:05 · answer #4 · answered by Zero_Lyfe 5 · 0⤊ 2⤋