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1. x/5 + x/7 = -36

2. x/3 - x/6 = 23

3. x/3 + 29 = -14

i havent did these in a long time ..and im having problems with them ...someone plz help

2007-05-30 13:53:25 · 4 answers · asked by fizzphattygurl34 1 in Science & Mathematics Mathematics

thank yall soo much but i have one more problem to solve and i keep gettin a decimal for it...

9x - 37 = 8x + 14

2007-05-30 14:13:51 · update #1

4 answers

1. Solve for "x"... x/5 + x/7 = -36

First: eliminate fractions - multiply the Greatest Common Denominator with each term which, is (5)(7) = 35.

(35)(x/5)+(35)(x/7)=(35)(-36)

(35x)/5+(35x)/7=(35)(-36)

7x+5x = -1,260

12x = -1,260

Sec: isolate "x" on one side (left) - divide both sides by 12.

12x/12 = (-1,260)/12

x = (-1,260)/12

x = -105

Follow the same format for the last two equations.

2007-05-30 14:05:30 · answer #1 · answered by ♪♥Annie♥♪ 6 · 0 0

I think...

1. (7x+5x)/35= -36
12x/35= -36
12x= -1260
x= -1260/12
x= -105

2. (2x-x)/6=23
x/6=23
x=138

3. x/3= -14 - 29
x/3= - 43
x= - 129

2007-05-30 21:16:04 · answer #2 · answered by Garo 2 · 0 0

1. x/5 + x/7 = -36
7x+5x=-36*35
12x=-36*35
x=-3*35
=-105


2. x/3 - x/6 = 23
2x-x=6*23
x=138

3. x/3 + 29 = -14
x/3=-14-29
x/3=-43
x=-3*43
= -129

2007-05-30 20:59:51 · answer #3 · answered by iyiogrenci 6 · 0 0

x/5 + x/7 = -36

Get a common denominator:

7x/35 + 5x/35 = -36
12x/35 = -36

Multiply both sides by 35 to get rid of the fraction;

12x = -1260

Divide both sides by 12 to get rid of the coefficient:

x = -105

You should be able to do all the others the same way.

2007-05-30 20:58:56 · answer #4 · answered by Anonymous · 0 0

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