Probability, is from Grade 8 but I don't remember?

Question

Container 1 holds eight red balls and four green balls; container 2 and 3 each hold two red balls and four green balls. A container is selected at random, and a ball is randomly selected from that container. What is the probability that the ball selected is green? Express your answer as a common fraction.

Answer 1

The probability of picking a given container is 1/3.
The probability of picking green for a given container is:
P(G) = #G/(#G + #R)

So for this problem we have:

P(G) = (1/3)[4/12 + 4/6 + 4/6] = (1/3)[1/3 + 2/3 + 2/3}
P(G) = (1/3)(5/3) = 5/9

Answer 2

the container is 1/3 and i think the green balls are 1/2

Answer 3

p(green, container 1) = 1/3
p(green, container 2) = p(green, container 3) = 2/3
p(container1) = p(container2) = p(container3) = 1/3;

Therefore the probability is (1/3)*(1/3) + (2/3)*(1/3) + (2/3)*(1/3) = 1/9 + 2/9 + 2/9 = 5/9