NO THIS IS NOT HOMEWORK!!
2007-05-30 13:22:00 · 13 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
First: multiply the 1st & 3rd term to get 6. find two numbers that giv eyou 6 when multiplied & 5 (2nd term) when added/subtracted. the numbers are (2 & 3). rewrite the expression with the new middle terms.
x^2 + 2x + 3x + 6 = 0
Sec: group "like" terms & factor both sets of parenthesis.
(x^2 + 2x) + (3x + 6) = 0
x(x + 2) + 3(x + 2) = 0
(x+2)(x+3) = 0
Third: solve the "x" variables - set both parenthesis to "0"
a. x+2 = 0
x+2-2=0-2
x = 0-2
x = -2
b. x+3 = 0
x+3-3=0-3
x = 0-3
x = -3
solutions: -3, -2
2007-05-30 13:43:12 · answer #1 · answered by ♪♥Annie♥♪ 6 · 1⤊ 0⤋
factor
x^2 + 5x + 6=0
(x+3)(x+2)=0
so either x+3=0, x+2=0 or both do
x+3=0, x= - 3
x+2=0, x= - 2
these are your two solutions
2007-05-30 13:24:54 · answer #2 · answered by jkicker 3 · 0⤊ 0⤋
yes 0
2007-05-30 13:41:22 · answer #3 · answered by Anonymous · 0⤊ 1⤋
X = (-2, -3)
2007-05-30 13:29:08 · answer #4 · answered by Stev 3 · 0⤊ 1⤋
thats becomes (x+3)(x+2)=0 when you factor it..and then (x+3)=0 or (x+2)=0
x= -3 or -2
yayyyyy
2007-05-30 13:25:37 · answer #5 · answered by Anonymous · 0⤊ 0⤋
Factor first.
(x + 3) (x + 2)
Set each equal to 0.
x + 3 = 0
so, x = -3
x + 2 = 0
so, x = -2
Your answers are..
x = -3,-2
2007-05-30 13:24:56 · answer #6 · answered by Glitter 5 · 0⤊ 0⤋
(x+2)(x+3) = 0. The roots are obvious.
2007-05-30 13:24:06 · answer #7 · answered by Anonymous · 0⤊ 1⤋
(x + 3)(X + 2) = 0
x = -3, x = -2
2007-05-30 13:25:22 · answer #8 · answered by richardwptljc 6 · 0⤊ 0⤋
the answer is (x+3) (x+2)
2007-05-30 13:25:38 · answer #9 · answered by softballchick26 3 · 0⤊ 1⤋
(x+2)(x+3)=0
x=-2 or -3
2007-05-30 13:31:22 · answer #10 · answered by Dave aka Spider Monkey 7 · 0⤊ 1⤋