It is possible if you have all the measurements and break it into several components. However, for an irregular object like this, the easiest method is fluid displacement.
2007-05-30 13:14:02
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answer #1
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answered by Phuzzy 2
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Tape over the hole in the guitar if it is acoustic and put it in
a cardboard box and cover the guitar with some of those
packing peanuts and shake the box so they settle under the neck. Get a piece of cardboard and put it level on top of the peanuts and mark the level inside the box. Now take the guitar out and find the new mark for the peanuts. Measure
the difference and multiply it by the inside length and width of the box. This gives a crude value and i don't think popcorn would give a better value. Sand is a bit dirty but the grains are very small and it flows. You would have to put plastic around the guitar. Water would probably seep in and affect the wood.
2007-05-30 21:00:11
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answer #2
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answered by knashha 5
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Yes, assume your guitar is cheap and you can sink it in a container full of water, measure the volume of water in the container before sinking the guitar in it.
Now sink the guitar in the container full of water and it will displace some of the water out, once the guitar is fullycover by the water, take it out .
then, the solution is "original volume minus the left volume of water in the container once the guitar is out, done.
2007-05-30 20:27:47
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answer #3
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answered by Diane L 1
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if you get a beaker big enough to fit a guitar in, then you can do it. The only way that I can think of getting the volume of an irregular object (aka the guitar) is to put water into the beaker at a certian mL, write the mL down onto a piece of paper before you put anything into the beaker, drop the irregular object into the beaker, write down the mL, and take the mL of the beaker without the irregular object and subtract it from the mL of the beaker with the irregular object.
2007-05-30 20:16:29
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answer #4
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answered by Ashley M 1
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water displacement
2007-05-30 20:21:27
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answer #5
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answered by Anonymous
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