solve this equation using square roots?

Question

x^2+ 20= 4

Answer 1

x^2+20=4
x^2=4-20
x^2= -16
thus x= root 16
so x= +or- 4

Answer 2

take the square root of both sides (after you subtract 20 from 4).

so you have x=sq root of -16

the sq root of 16 = 4, but since it's negative it is imaginary, needing an i.

so x = 4i.

Answer 3

x^2+20=4
x^2+20-20=4-20
X^2=-16
x= +/- 4i

Answer 4

with the intention to resolve those sq. roots situation, take the sq. root on the two sides. enable / be the sq. root image as i can not make that image on my laptop at this 2nd. a million. /(2x+a million)^2 = /25 <-----------From right here we are waiting to get out: (2x+a million) = 5 <-----------The sq. roots yield those solutions. Now you have the bases of your equation. basically resolve for x now: 2x = 5 - a million <-----------At this element I relatively have moved the a million from the left section to the terrific as we ought to get the x by myself. 2x = 4 <-----------Divide the two sides via 2 to get x in basic terms x = 2 <------------your answer I did one for you, #2 is carried out an identical way as I confirmed you. try it your self.

Answer 5

x^2 + 20 = 4
x^2 = 4 - 20
x^2 = -16
x^2 = -1 * 16
x = sqrt(-1 * 16)
x = sqrt(-1) * sqrt(16)
x = i * +/-4
x = +/-4i

Answer 6

plus or minus 4i.

Answer 7

Cool! I failed math☻

Answer 8

do your own homework