A submarine changes depth by altering its
a. speed
b. density
c. total area
d. shape
A:b
2007-05-30 12:58:11 · 7 answers · asked by Ryoma Echizen 3 in Science & Mathematics ➔ Physics
B is partly correct. The sub changes density by filling/blowing balast tanks. A submarine also uses its diving planes to change its angle so it can propel itself up and down.
2007-05-30 13:03:21 · answer #1 · answered by Anonymous · 0⤊ 0⤋
B--Density. By pumping water in and out of it's ballast tanks, the ship will either float or sink. For maneuverability, the computer attempts to find a neutral buoyancy and front to back balance where the ship with neither sink nor float but can then be controlled much like a plane by using a type of Ailerons and tail wing pitching and could also come to a full stop and just hang silently under the water.
2007-05-30 13:14:52 · answer #2 · answered by Jeffrey F 6 · 0⤊ 0⤋
You can change a boat's depth in different ways. The normal way is by changing its shape, i.e. changing the angles on its planes, when changing depth while operating at depth.
You can also change its overall density, i.e. add/subtracting ballast. This last is used when diving/surfacing. You can also change its depth by changing speed. Since boats normally maintain a slight positive bouyancy and use planes to maintain depth, if you lose propulsion the boat will normally rise to the surface, albeit slowly. This is a safety practice, in case power is lost. One would want to put the boat "on the roof" if propulsion/power went away.
2007-05-31 05:44:45 · answer #3 · answered by SSN695ELT 2 · 0⤊ 0⤋
The answer IS b. It can't change its shape, or area. It can change its speed but that alone wouldn't make it go up or down. By taking on ballast, it changes its density.
2007-05-30 13:07:31 · answer #4 · answered by Joseph F 5 · 0⤊ 0⤋
Your speed is 20 inches/sec, no longer 20 mph. this is an time-honored speed, no longer an exceedingly final speed. Your very final speed will equivalent 2(v avg)- vi if we anticipate consistent acceleration. vf= 2va-vi vf=2(20)-0= 40 inches/sec you are able to then use the equation a= (vf-vi)/t to locate your acceleration. a=40/2=20 inches/sec^2 you are able to then convert that to mph^2 in case you desire.
2016-10-06 08:36:08 · answer #5 · answered by ? 4 · 0⤊ 0⤋
b
2007-06-03 11:19:26 · answer #6 · answered by johnandeileen2000 7 · 0⤊ 0⤋
yes it is b
2007-05-30 13:01:18 · answer #7 · answered by rosie recipe 7 · 0⤊ 0⤋