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12 answers

If you allow factorials, you can get infinitely large.
9^9^9^9 is a good try, but why stop there?
(9^9^9^9)! is bigger.
((9^9^9^9)!)! is bigger still.
You can keep adding exclamation marks to get a number as big as you want.

2007-05-30 13:08:14 · answer #1 · answered by Bramblyspam 7 · 1 0

How many different mathematical symbols are we allowed to use?
If none, then 9998, or 9^9^9^9 if ^ doesent count.
But if we can use as many as we want, 9999!!!!!!!!!... (with a lot, or infinite number of factorials, thus the number being infinity).
If only one factorial then 9999!.
I am not sure if 9^9^9^9 or 9999! is larger, but i think it is 9999!

2007-05-30 13:11:25 · answer #2 · answered by Alex 4 · 0 0

I think here no symbols and characters are allowed. Since the question is simply "What's the largest number you can make with 4 digits?"
So, it should be => 9 to the 9th power of 9th power of 9

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2007-06-05 12:21:26 · answer #3 · answered by Anonymous · 0 0

Well 9999! would be a pretty large number. It would probably take up to at least one page to type the entire product number.

2007-05-30 13:09:29 · answer #4 · answered by UnknownD 6 · 0 0

well, infinity isnt really a digit, so im gonna say 1234 times infinity
if that doesnt work, im gonna have to say 999/0+
thats 999 divided by the smallest possible number above 0

2007-06-06 15:21:23 · answer #5 · answered by Anonymous · 0 0

9^9^9^9

2007-06-05 18:23:34 · answer #6 · answered by sachin p 1 · 0 0

9^9^9^9

2007-06-04 05:59:51 · answer #7 · answered by Brave 3 · 0 0

9^9^9^9. you get something that, in scientific notation, goes out 653 places.

2007-05-30 13:00:32 · answer #8 · answered by DXFlounder 2 · 0 0

9998

2007-06-06 11:56:22 · answer #9 · answered by Nique 1 · 0 0

9998

2007-05-30 13:03:03 · answer #10 · answered by needsumthin2002 3 · 0 0

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