Okay so NaHCO3 + CH3COOH ———> NaCH3COO + H2O + CO2 right?...so if i used 1.02 grams of the base 10 ml of the acid and after heating until all the water evaporated and ended up with 1.0 gram of white residue(sodium acetate) would that make sense? Also could you show me how would i calculate the concentration of the acid and the amount of water and carbon dioxide produced?
2007-05-30 12:05:00 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
this is a stoichiometry problem
you have 1.02 g of NaHCO3. COnvert that to moles using the molar mass. The molar ratio so 1:1 so you also have moles of acetic acid.
The moles of acetic acid are dissolved in .01 liters. SO divide the two and you have molarity. This is the measure of concentration.
To solve the rest of your questions, just complete the stochiometry for water and CO2
2007-05-30 12:16:20 · answer #1 · answered by reb1240 7 · 0⤊ 0⤋